Einstein

That may be the last we see of Hyde in a Bills uniform. 😔

I don’t know about letting up, but momentum is absolutely real. Despite what Schopp says.

Every time we got into a X and long scenario, we give up 10-15 yards. Incredibly frustrating.

Oh shut up.

100% PI on Kelce.

Hate giving up 3rd and longs because it gives the offense momentum. We had the perfect chance to stop their drive there.

It’s amazing how this team can stop 3rd and 5 but give up 3rd and 18.

Allen literally saved this drive by that pirouette. There is only 1 other QB in the NFL who could make that play (Lamar).

Love him.

What do you think the ref was telling Josh

Let’s go Ed!!!

I get that. But this isn’t 1980 anymore. We just had a team hit a 59 harder against us - in a rainstorm.

1) If we can’t trust Bass to hit field goals from the 40, why even have him? 2) I wish Allen took off running on 2nd down.

Why would you try to beat the snap on a punt!?

McCaffrey proves every week that he is worth every cent and every draft pick.

If the Bills win, there will be 6 teams with a 7-6 record after today. For each of the 6 teams to end up at 9-8 or worse, they would need to win 2 out of their last 4 games via any combination. Each of these scenarios has a 1/2 * 1/2 * 1/2 * 1/2 = 1/16 chance of occurring. Since there are 6 teams, you would multiply this probability by 6 to account for all 6 teams having the same chance of ending up at 9-8 or worse: 6 * (1/16) = 6/16 (or 3/8). So, there is a 3/8 or 37.5% chance that at least one team out of the 6 will end up at 9-8 or worse, which would potentially open up a playoff spot for a 9-8 team. For simplicity sake. we can multiply them together to find the probability that all 6 teams end up at 9-8 or worse: (3/8) * (3/8) * (3/8) * (3/8) * (3/8) * (3/8) = (3/8)^6 ≈ 0.00390625 So, there is approximately a 0.39% chance that all 6 teams end up at 9-8 or worse, assuming they each have a 37.5% chance of winning 2 out of their last 4 games. But of course we only need 2 teams to get to 9-8 and the remaining teams to lose more than 8. Scenario 1) 2 teams lose 8 games and 4 lose more than 8. Scenario 2) 4 teams lose 8 games, and 2 teams lose more than 8 games. 15 * (3/8)^2 * (5/8)^4 ≈ 0.1398 So, there is approximately a 13.98% chance that 2 out of the 6 teams lose 8 games, and the remaining 4 teams lose more than 8 games, That doesn’t even take into consideration the rams who currently have 7 losses and could lose just 1 more. Or tiebreakers or common games. Just saying, the probability is low.

Every time I turn the Jags game on, Lawrence gets picked. He’s throwing them up like Peterman.

The Texans play a terrible Titans team next week. Not sure they lose even if Stroud is out.

Very little chance of that It would take a multitude of teams losing 2 of their last 4 games. 10-7 should make it - but due to losing nearly every tiebreaker, we can’t trust that.

Ouch CJ Stroud down. Concussion?

Agree with the sentiment, but an 18 point lead with 6 minutes left is even too much for the Jets.

Jets came in clutch for us today.

This Cinci game is reaffirming my belief that the Burrow is overrated. This Bengals offense is just pitch and catch.

Oh wow Bengals. Eek.

Is Minshew the new Fitz? He seems like an ideal backup. Good enough to win some games but not start material.