bartshan-83 Posted July 27, 2010 Share Posted July 27, 2010 YESTERDAY: 1. mephiSTOPhelean telecomMUTE imMODEst reINFOrcements cENTERpiece balLISTics 2. SWEDEN MONACO SERBIA CYPRUS POLAND NORWAY (WARSAW is the capital) 3. 1/4...nice job links with the graphical proof. TODAY: 1. Each answer is a seven-letter word or name that ends in O. Each answer starts with a different letter of the alphabet. 1. Canadian province 2. Hot sauce 3. Keepsake 4. Hitchcock film 5. Inert medication 6. Below freezing C. 7. Hellfire 8. Fake courage 9. Beethoven opera 10. Spicy sausage 2. One arrangement of the letters in the word PUPPET is UETPPP, but this ends with the letter P. How many different six-letter arrangements of the letters of the word PUPPET are there that neither begin nor end with P? (213) Link to comment Share on other sites More sharing options...
JÂy RÛßeÒ Posted July 27, 2010 Share Posted July 27, 2010 TODAY: 1. Each answer is a seven-letter word or name that ends in O. Each answer starts with a different letter of the alphabet. 1. Canadian province 2. Hot sauce 3. Keepsake 4. Hitchcock film 5. Inert medication 6. Below freezing C. 7. Hellfire 8. Fake courage 9. Beethoven opera 10. Spicy sausage ONTARIO TABASCO MEMENTO VERTIGO PLACEBO SUBZERO INFERNO BRAVADO FIDELIO CHORIZO 2. One arrangement of the letters in the word PUPPET is UETPPP, but this ends with the letter P. How many different six-letter arrangements of the letters of the word PUPPET are there that neither begin nor end with P? 72 - 4X3X2X3 this is a guess Link to comment Share on other sites More sharing options...
shrader Posted July 27, 2010 Share Posted July 27, 2010 2. One arrangement of the letters in the word PUPPET is UETPPP, but this ends with the letter P. How many different six-letter arrangements of the letters of the word PUPPET are there that neither begin nor end with P? (213) I'll screw up and skip a step, but here we go: 3 different starting non-p letters 2 other non-p letters left for the end 3*2=6 possible combinations for the first/last letter That leaves 3 Ps and 1 other letter for the middle 4 spaces. It doesn't matter which P is placed where, so there are 4 possible combinations here. 6*4=24 total arrangements. Link to comment Share on other sites More sharing options...
linksfiend Posted July 27, 2010 Share Posted July 27, 2010 1. I couldn't come up with or Subzero or Fidelio. 2. I also got 24. The middle four characters will be three Ps and the leftover non-P (X) which forms 4 combinations -PPPX- -PPXP- -PXPP- -XPPP- The 3 non-Ps give you 6 different combos for the first and last letter: E-4-T E-4-U T-4-E T-4-U U-4-E U-4-T -------- X-24-X Link to comment Share on other sites More sharing options...
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